show that (3x+ 7) ² - 8x = (3x-7)^2
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(3x+7)²-8x = (3x-7)²
RHS = (3x-7)²
= 9x²+ 49 - 42x
LHS = (3x+7)²-8x
= 9x²+49+42x-8x
So RHS ≠ LHS
Answered by
10
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