Math, asked by susmithdoddipalli, 9 months ago

show that (3x+y+z)^3+(x+3y+z)3)^3+(x+y+3z)^3-3(3x+y+z)(x+3y+z)(x+y+3z)=20(x^3+y^3+z^3-3xyz)

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Answered by kesevan2906

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