Question

show that 4√2 is an irrational number​

Answer 1

Answer:

Let us assume that 4√2 is a rational number.

So, we can find co-prime integers ‘a’ and ‘b’ (b ≠ 0) such that

4√2 = a/b

∴ √2 = a/4b

Since, a and b are integers, a/4b is a rational number and so √2 is a rational number.

Step-by-step explanation:

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Answer 2

Answer:

4 is a rational number and 2 is an irrational no we know that the quotient of rational no and irrational is irrational so 4 underoot is an rational no