Question

Show that 4-3root3 is an irrational number

Answer 1

Consider, 4−3√3 

Let 4−3√3 = (a/b) a rational number 

 ⇒ −3√3 = (a/b) − 4

⇒ −3√3 = (a − 4b)/b 

⇒ √3 = (a − 4b)/(−3b) Since a, b are integers, then (a − 4b)/(−3b) represents a rational number. But this is a contradiction since RHS is a rational number where as LHS (√3) is an irrational number Hence our assumption that " 4−3√3 = (a/b) is a rational number" is incorrect.

Thus  4−3√3 is an irrational number   

❣️⭐I hope you mark as brainliest answer⭐❣️✨✨✨