Question

show that (4,4) (3,5) (-1, 1) are vertices of
right triangle ​

Answer 1

Answer:

(-1,1)

Step-by-step explanation:

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Answer 2

Step-by-step explanation:

let's consider a triangle ABC. let A be (4,4) , B be (3,5) and C be (-1,1) . and we have sides of traingle namely AB,BC and CA.

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so now we calculate the distance of each side of the triangle by using distance formula to calculate distance between any 2 points .

AB= √((4-3)^2 +(4-5)^2) =√2

BC=√((3+1)^2 +(5-1)^2) =4√2

CA=√((-1-4)^2 +(1-4)^2)= √34

so according to Pythagoras theorem ..it states that In a right-angled triangle, the square of the hypotenuse side is equal to the sum of squares of the other two sides

so AB^2 + BC^2 must be equal to CA^2 if triangle ABC is right angled triangle.

so we put the values of each side and verify this theorem

(√2)^2 + (4√2)^2 = 34 which is equal to the square of CA i.e 34 .

Hence it is a right angled triangle.