Question

Show that 4^n can never end with digit zero for any belongs to natural number​

Answer 1

Step-by-step explanation:

4^n can be written as (2×2)^n

so to end with it should have both 2 an5 as factors

but it contains 2 only for any value of n

so 4^n cannot end with zero

Answer 2

as we know that

4power n has the factor

2power n * 2power n

so it will not end with digit 0

as we need factor as 2power a * 5 power m

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