show that 4 root 2 is an irrational number
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Answer:
Step-by-step explanation:
Let 4√2 be rational number
Then 4√2=p/q
where q≠0, p and q are integers
4√2=p/q
√2=p/4q
Where √2 is irrational and
p/4q is rational
Our assumption is wrong,because LHS≠RHS
So 4√2 is a irrational number
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answer 4root2 is rational no
4root2=p/q[p and q is co prime no]
root3= p/2q
root3 is irrational no
LHS is not equal RHS
IT IS CONDRICTION asuuming is wrong 4root 2is an irrational no
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