Question

Show that: (4ab+3cd)² – (4ab-3cd)²/48 = abcd​

Answer 1

To show the result is abcd, we need to expand the brackets to find the value.

→ (4ab+3cd)² - (4ab-3cd)²

= (16a²b²+24abcd+9c²d²) - (16a²b²-24abcd+9c²d²)

Now there are common on both brackets.

→ 48abcd

Now divide by 48 and we get abcd.

Answer 2

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