Question

Show that :
(4ab + 3cd)2 – (4ab – 3cd)2
-= abcd
48​

Answer 1

Step-by-step explanation:

${(4ab + 3cd)}^{2} - {(4ab - 3cd)}^{2} \\ ( {x}^{2} - {y}^{2} = (x + y)(x - y)) \\ = > (4ab + 3cd + 4ab - 3cd) (4ab + 3cd - 4ab + 3cd) \\ = > (8ab)(6cd) \\ = > 48abcd \\ \\ \\ hence \: shown \\ mark \: brainliest \: please$