Question

Show that (4pq+3q^2) - (4pq-3q^2) =48pq^2

Answer 1

Step-by-step explanation:

(4pq+3q)^2 −(4pq−3q)^2 =48pq^2

LHS=(4pq)^2 +2 (4pq)(3q)+ (3q)^2 −[(4pq) −2(4pq)(3q)+(3q)^2]

=16p^2 q^2 +24pq^2 +9q^2- 16p^2q^2+24q ^2 −9q^2

=48pq^2

=RHS

therefore LHS=RHS

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