Question

Show that:(4pq+3q)²-(4pq-3q)²=48pq

Answer 1

we know that 
$( a+b)^{2} -(a-b)^{2} =4ab$
so $(4pq+3q)^{2} -(4pq-3q)=4(4pq)(3q$
=48p$q^{2}$
                                                  hope i helped you

Answer 2

(4pq+3q)²=16(pq)^2+24pq^2+9q^2(4pq-3q)²=16(pq)^2-24pq^2+9q^2therefor (4pq+3q)²-(4pq-3q)²=48pq^2