Question

SHOW THAT:- (4pq+3q)²-(4pq-3q)²=48pq²​

Answer 1

Answer:

Step-by-step explanation:

given that : (4pq + 3q)² – (4pq – 3q)² = 48pq²

As we know,

(a + b)² = a² + b² + 2ab

and

(a – b)² = a² + b² – 2ab

So, we have to apply the above identities in the given equation.

(4pq + 3q)² – (4pq – 3q)² = L.H.S.

= (16p²q² + 9q² + 24pq²) – (16p²q² + 9q² – 24pq²)

= 16p²q² + 9q² + 24pq² – 16p²q² – 9q² + 24pq²

= 24pq² + 24pq²

= 48pq²

= R.H.S.

hence proved

hoping my this answer will help you.

Answer 2

Answer:

hence proved

Step-by-step explanation:

it's of form a^2-b^2

a^2-b^2=(a-b)(a+b)

(4pq+3q)^2-(4pq-3q)^2=

(4pq +3q -4pq+3q)(4pq+3q+4pq-3q)=

(6q)(8pq)

=(48pq^2)