Math, asked by anvi123hpr, 1 year ago

Show that.
(4pq + 3q)² - (4pq-3q)² = 48pq²

Please kindly solve it on a piece of paper


vaibh2: yes
akhil160: 4pq + 3q)² – (4pq – 3q)² = 48pq²

As we know,
(a + b)² = a² + b² + 2ab
and
(a – b)² = a² + b² – 2ab

So, we have to apply the above identities in the given equation.

(4pq + 3q)² – (4pq – 3q)² = L.H.S.

= (16p²q² + 9q² + 24pq²) – (16p²q² + 9q² – 24pq²)

= 16p²q² + 9q² + 24pq² – 16p²q² – 9q² + 24pq²

= 24pq² + 24pq²

= 48pq²

= R.H.S.
Anonymous: LoL you copied my ans.

Answers

Answered by Nikki57
213
Hey!

________________

Refer the pic for answer.
We simply used identities.

________________

Hope it helps...!!!

Attachments:

sanjayprajapati: thanks
Seemapanday: soory I can't do because I am in 8th class
ramadugusrinivas: thanks
harshit3555: 48q2 bcz (a+b)2 +(a-b)2 is a2 +b2+-2ab so answer is 48q2
Nikki57: :)
kmpathak10403: use identity a2-b2 so( 4pq+3q+4pq-3q) (4pq+3q-4pq+3q). after solving that 8pq*×6q=48pq2 = rhs
kmpathak10403: this is right identity
praghalbha2: hi
harshita146: (a+b)2=a2 +b2 +2ab +(a-b)2=a2 + b2 - 2ab use this formula
kmpathak10403: kyun
Answered by Anonymous
292
Hey\:There

I don't have a pen & paper with me right now. I'm texting here.
___________________________

(4pq + 3q)² – (4pq – 3q)² = 48pq²

As we know,
(a + b)² = a² + b² + 2ab
and
(a – b)² = a² + b² – 2ab

So, we have to apply the above identities in the given equation.

(4pq + 3q)² – (4pq – 3q)² = L.H.S.

= (16p²q² + 9q² + 24pq²) – (16p²q² + 9q² – 24pq²)

= 16p²q² + 9q² + 24pq² – 16p²q² – 9q² + 24pq²

= 24pq² + 24pq²

= 48pq²

= R.H.S.
__________________________

Hope\:my\:ans.'s\:satisfactory.(^-^)

Vaishnavraj: gr8 dear
kmpathak10403: yes
kmpathak10403: itna dimag lgane ki kya jarurat
kmpathak10403: oversmartnessss
rakeshsingh2: nice
rakeshsingh2: nice
ramadugusrinivas: yah
Nickhy: Wah yar bhaut hi achaaa
kmpathak10403: ☺☺☺
zubair29: hey we can directly solved the equation by a2 - b2
Similar questions