Question

show that 4sinA. sin(60°+A).sin(60°-A)=sin3A
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Answer 1

Answer:

LHS = 4 sin A sin(60° + A). sin(60° – A) = 4 sin A{sin (60° + A). sin (60° – A)} = 4 sin A {sin2 60° – sin2 A)} Read more on Sarthaks.com - https://www.sarthaks.com/911175/show-that-4-sin-a-sin-60-a-sin-60-a-sin-3a