Question

show that 5-2√3 is irrational no.​

Answer 1

Answer:

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$let \: 5 - 2\sqrt{3} is \: rational \: number \\ = 5 - 2 \sqrt{3 =} = \frac{a}{b} (where \: a \: and \: b \: are \: coprime \: and \: b \: not \: equal \: to \: zero \\ - 2 \sqrt{3} = \frac{a}{b} \: - 5 \\ \sqrt{3 } = \frac{a}{b } \: - 5 \frac{ - 2} \\ \frac{a}{b} - 5 \: is \: rational \: number \\ rational \: number \: divided \: by \: a \: rational \: number \: is \: also \: rational \: number \: .but \: \sqrt{3} \: is \: irrational \: number \\ our \:suppostion \: is \: wrong$