show that 5+2√7 is an irrational number where √7 is
given to be an irrational number
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Step-by-step explanation:
Let us assume to the contrary that 5 + 2√7 is rational.
5 + 2√7 = a / b. (a and b are coprimes)
(5 + 2√7)² = a² / b²
25 + 20√7 + 28 = a² / b²
20√7 = a² - 53 / b²
√7 = a² - 53 / b² . 20
Since a and b are integers,
a² - 53 / b² . 20 is rational....
But this contradicts the fact that √7 is irrational...
Thus, 5 + 2√7 is an irrational number..
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