show that √5 + √2 is irrational
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Step-by-step explanation
Use proof by contradiction. Assume that the sum is rational, that is
2–√+5–√=ab
where a and b are integers with b≠0. Now rewrite this as
5–√=ab−2–√.
Squaring both sides of this equation we obtain
5=a2b2−22–√ab+2.
Now, carefully solve for 2–√ and obtain
2–√=−3b2a+a2b.
This implies that 2–√ is a rational number which is a contradiction. Thus
2–√+5–√
is an irrational number.
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