show that 5+3√2 is irrational
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Answered by
49
Step-by-step explanation:
Let us assume the contrary.
i.e; 5 + 3√2 is rational
∴ 5 + 3√2 = a/b, where ‘a’ and ‘b’ are coprime integers and b ≠ 0
3√2 = a/b – 5
3√2 = a−5b/b
Or √2 = a−5b/3b
Because ‘a’ and ‘b’ are integers a−5b/3b is rational
That contradicts the fact that √2 is irrational.
The contradiction is because of the incorrect assumption that (5 + 3√2) is rational.
So, 5 + 3√2 is irrational
hope it is helpful for you sister.
Answered by
7
here's your answer
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