Show that 5-√3 is a rational number
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by that method we prove that it
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let 5-√3 is a rationl no
so, 5-√3 can also be written into p/q form
5-√3 =P/q
-√3 =p/q -5
-√3 = p-5q/q
√3 = -(p-5q/q)
√3 = 5q -p /q
5q -p / q is a rational no and √3 is an irrational no
irrational can not be equal to rational.
so our contradiction is wrong
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