show that (5-√3) is an irrational no. if it is given that (√3) is a irrational no.
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Answer:
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Step-by-step explanation:
Let us assume the given number be rational and we will write the given number in p/q form
⇒5− √3 = p/q
⇒ √3= 5q−p/q
We observe that LHS is irrational and RHS is rational, which is not possible.
This is contradiction.
Hence our assumption that given number is rational is false
⇒5− √3
is irrational
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