Math, asked by bangarneha73, 1 month ago

Show that 5 + √7 is an irrational number.

Answers

Answered by ItzMeMukku
2

{ \large{ \sf{ \underbrace{\underline{\bigstar \:Answer:}}}}}

Hence proved that the given \sqrt 5+ \sqrt 7

is an irrational number

{ \large{ \boxed{ \pink{ \underline{ \bf \:To\: prove:}}}}}

To prove whether

\sqrt 5+ \sqrt 7

is irrational or not.

\tt{Solution:}

Let us assume that

\sqrt 5+ \sqrt 7

be rational, and let p/q are co-prime where q is not equal to zero (0).

\begin{gathered}\begin{array} { l } { \sqrt { 5 } + \sqrt { 7 } = \frac { p } { q } } \\\\ { \sqrt { 5 } = \frac { p } { q } - \sqrt { 7 } } \\\\ { \sqrt { 5 } = \frac { p - \sqrt { 7 } q } { q } } \end{array}\end{gathered}

We know that

\sqrt 5

is irrational while p/q form is rational.

Hence it contradicts our assumption of \sqrt 5+ \sqrt 7

is rational.

~ Hence, it is proved that \sqrt 5+ \sqrt 7 is irrational.

Done :)

Thankyou :)

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