Question

show that 5 + √7 is an irrational number .
​

Answer 1

Let us assume that 5 + √7 is a rational number

where, b≠0 and a, b are integers

∵ a, b are integers ∴ a – 5b and b are also integers

is rational which cannot be possible ∵

which is an irrational number

∵ it is contradicting our assumption ∴ the assumption was wrong

Hence, 5 + √7 is an irrational number

Answer 2

Step-by-step explanation:

Let us assume that 5 + √7 is a rational number

5+√7=a/b

where, b≠0 and a, b are integers

=>√7= a/b-5

=>√7=a-5b/b

∵ a, b are integers ∴ a – 5b and b are also integers

= a-5b/b

is rational which cannot be possible ∵

a-5b/b =√7

which is an irrational number

which is an irrational number∵ it is contradicting our assumption ∴ the assumption was wrongHence, 5 + √7 is an irrational number

hope it help u❤

hi

how r u