Show that 5 is the zero of the polynomial x cube minus 3x square minus x plus 3
Answers
Answered by
2
Heya !!!
X = 5
P(X) = X³ - 3X² - X +3
P(5) = (5)³ - 3 × (5)² - 5 + 3
=> 125 - 3 × 25 - 2
=> 125 - 75 -2
=> 125 - 77
=> 48
Reminder # 0 [ Where # stand for not equal ]
Hence,
5 is not a zero of the given polynomial.
★ HOPE IT WILL HELP YOU ★
X = 5
P(X) = X³ - 3X² - X +3
P(5) = (5)³ - 3 × (5)² - 5 + 3
=> 125 - 3 × 25 - 2
=> 125 - 75 -2
=> 125 - 77
=> 48
Reminder # 0 [ Where # stand for not equal ]
Hence,
5 is not a zero of the given polynomial.
★ HOPE IT WILL HELP YOU ★
Answered by
1
If 5 is the zero of given equation, remainder must be 0,
So,
x³ - 3x² - x + 3 should equal to 0
(5)³ - 3(5)² - 5 + 3
125 - 75 - 2
125 - 77
48
As 48≠0
Hence, 5 is not the factor of given equation.
I hope this will help you
(-:
So,
x³ - 3x² - x + 3 should equal to 0
(5)³ - 3(5)² - 5 + 3
125 - 75 - 2
125 - 77
48
As 48≠0
Hence, 5 is not the factor of given equation.
I hope this will help you
(-:
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