Question

show that 5^n cannot end with digit 2 for any natural number n

Answer 1

Solution :-

》given by :- the from 5^n

》according to question :-

》natural numbers (n= 0,1,2,3,4.....)

we have,

》if n=0 then 5^0 =1

》if n=1 then 5^1 = 5

》if n=2 then 5^2 =25

》similarly

》if n=3 then 5^3 =125

》here we fineded that evry condition 5^n cannot end with digit 2 for any natural number n.

☆i hope its help☆

Answer 2

Here is your answer user.

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