Question

show that 5 under root 6 is an irrational number​

Answer 1

Answer:

root a23 ;:4} helping out

Answer 2

HINT: Just prove that $\sqrt{5}$ is irrational as $\sqrt[6]{5}$ is just the cube root of

If you manage to prove $\sqrt{5}$ then you can say that the cube root of an irrational number is always irrational .

In case you are not able to prove $\sqrt{5}$ is irrational then just ask i will upload the full solution (✿◠‿◠)