Show that 5 - V3 is irrational
Answers
⭐SOLUTION⭐
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Let us assume 5-√3 as rational, then we have
⇒5-√3 is rational
⇒5-(5-√3 ) is rational [difference of rational is always rational]
⇒√3 is rational,
Now √3 is rational so we know that rational number can be express in the form of a/b where b is not equal to zero and a and b have no common factor other than 1
⇒√3=a/b
Squaring both sides
⇒(√3)²=a²/b²
⇒3=a²/b²
⇒3b²=a² ‐-----(1)
Thus 3 divides a² and also 3 divides a.
Let a=3c for some numbers c .
Putting a²=3b² from (1)
⇒3b²=9c²
⇒b²=3c²
Thus 3 divides b² and also divides b.
Thus 3 is common factor of a and b .
But, this contradicts the fact that a and b have no common factor other than 1
This wrong contradiction arises by our wrong assumption √3 as rational , thus √3 is irrational.
Now we know that √3 is irrational but as we have assumed 5-√3 as rational then √3 becomes rational, So this all contradiction arises be our wrong assumptions.
Thus 5-√3 is irrational.