Question

Show that 5root3 is a irrational number​

Answer 1

let us assume that 5√3 is rational . So ,

$5 \sqrt{3} = \frac{a}{b}$

Where a and b are Co - primes ...

$\sqrt{3} = \frac{a}{5b}$

here for a and b are positive integers...

a /5b is in the form of a/b

So, √3 should be rational...

but this contradicts the fact that √3 is irrational...

Therefore 5√3 is irrational..

• I hope it helps you.....

Answer 2

Answer:

Then it can be written in the

form5 - root3

= p/qor 5 - p/q = root3

It implies root3 is a rational number

[Since 5 - p/q are rationals]