Question

show that √6+√2 is a irrational number​

Answer 1

Step-by-step explanation:

Let 6+root 2 is a rational number then we get that a and b two co-prime integers. ... Therefore (6-a/b)is a rational number and So root also is a rational number. But it is contradiction to fact root 2 =(6-a/b) is rational number. So we that 6+root 2 is an irrational number.

Answer 2

Answer:

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Step-by-step explanation:

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