show that 6, 5⅓, 4⅔,.... is an A.P. Find it's 10 term
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Step-by-step explanation:
a=6
t2=5⅓
t3=4⅔
a-t2= 6-5⅓ = ⅔
t2-t3= 5⅓-4⅔ = ⅔
diffence between consecutive trems is constant hence is in AP
a=6 d=-⅔
t10 = a+(n-1)d
=6+(10-1) -⅔
=6-18/3
=(18-18)/3
=0/3=0
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