Question

show that 6,8and 10 form Pythagoras triplets​

Answer 1

Answer:

Step-by-step explanation:

Pythagoras Theorem: In a right triangle, the area of the square on the hypotenuse is equal to the sum of the areas of the squares of its remaining two sides.

(Hypotenuse)  

2

=(Perpendicular)  

2

+(Base)  

2

 

(AC)  

2

=(CB)  

2

+(BA)  

2

 

For Pythagorean triplets:  

a  

2

+b  

2

=c  

2

 

a=6

b=8

c=10

∴6  

2

+8  

2

=36+64=100=10  

2

 

That is a  

2

+b  

2

=c  

2

 

Hence 6,8,10 are Pythagorean triplets.

solution

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Answer 2

Answer:

10^2 = 6^2 + 8^2

100= 36+ 64

Step-by-step explanation:

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