Question

show that 6 by 2 root 3 is an irrational number​

Answer 1

Answer: Assume that 6+2√3 is rational

6+2√3 = a/ b where a and b are co- prime integers

2√3= a-6b/b

√3= a - 6b / 2b

RHS is of the form p/ q LHS is also rational

but it Contradicts the fact that √3 is irrational due to our incorrect assumption that 6+2√3 is rational , Hence 6+2√3 is irrational

Answer 2

Answer:

Step-by-step explanation:

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