show that 6^n can never end with digit 2 ??
i need the answer in a proper proof dont spam content quality required...
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this can be proven as follows
6^1 = 6
6^2= 36
6^3 = 216
6^4= 1296 .
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6^n also ends with 6 but not 2
6^1 = 6
6^2= 36
6^3 = 216
6^4= 1296 .
.
.
6^n also ends with 6 but not 2
ANMOLSEHGAL007:
i need proper proof
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