Math, asked by bhuramteke2005, 8 months ago


Show that 6^n cannot end with the digit 0 for any natural number n.​

Answers

Answered by kusumresearch
0

Answer:

It can be observed that 5 is not in the prime factorisation of 6n. Hence, for any value of n, 6n will not be divisible by 5. Therefore, 6n cannot end with the digit 0 for any natural number n.

Previous Question
Next Question
Similar questions
Math, 4 months ago
• The centre of rotation of an equilateral triangle is its The centre of I think it's intersection of diagonals am I correct please tell​...
Computer Science, 4 months ago
Html files are saved with the _________ extension​...
Math, 4 months ago
10. Which angles in the adjacent figure are acute and which are obtuse ? Check your estimation by measuring them. Write their measures too.​
History, 8 months ago
hi sub history please tell if know so only​...
Science, 8 months ago
how will a single cell carry on the complete life in a unicellular organism ​...
Math, 1 year ago
Divide 1419 into three parts so that the second number is 2/3rd of the first and third number is 4/5th of the second The sum of digits of a two-digit number is 9. If the new number formed by reversing the digits is greater than the original number by 45, Find the original number. 26. -The digit in ten's place of a 2-digit number is four times that in the unit's place. If the digits are reversed,...
Sociology, 1 year ago
what is the unploment rate of nepal​...
Social Sciences, 1 year ago
what is known as directive principles of state policy?