Question

show that 6 root 5 is irrational

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Answer 1

Let us assume is rational write it in form.

So, we can write this number as

$6\sqrt{5}$ = $\frac{a}{b}$  ---- (1)

Here, a and b are two co-prime numbers and b is not equal to zero.

Simplify the equation (1) divide by 7 both sides, we get

$\sqrt{5}$ = $\frac{a}{6b}$

Here, a and b are integers, so $\frac{a}{6b}$ is a rational number, so $\sqrt{5}$​ should be a rational number.  

But,   is an irrational number, so it is contradictory.

Therefore, is an irrational number.

Answer 2

Step-by-step explanation:

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