Question

Show that: (6a – 5b)2 – (6a +5b)2 = - 120 ab

Answer 1

Solutions :

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Step-by-step explanation:

Given equation :

☞$\sf{(6a-5b)^2-(6a+5b)^2)=-10ab}$

LHS:

☞[tex]\sf{(6a-5b)^2-(6a+5b)^2}[/tex]

☞$\sf{(36a^2+25b^2-60ab)-(36a^2+25b^2+60ab)}$

☞$\sf{(36a^2+25b^2-60ab-36a^2-25b^2-60ab)}</p><p>$

☞$\sf{(-60ab-60ab)}$

☞$\sf{(-120ab)}$

☞$\bf{the LHS will be -120ab}$

☞RHS:

☞$\sf{-120ab}$

☞LHS=RHS=-120ab

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Answer 2

Answer:

We have to use the formula

(a+b)^2 =a^2+b^2+2ab.

(a-b)^2=a^2+b^2-2ab

=(6a-5b)^2 -(6a+5b)^2

=36a^2+25b^2-60ab-(36a^2+25b^2+60ab)

=36a^2+25b^2-60ab-36a^2-25b^2-60ab

= -120ab

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