Question

show that 7-√5 is irrational, given that √5 is irrational.

Answer 1

Let , 7-root5 is a rational no. is equals to r, where r is a rational no.
So,
7-root 5 = r
7-r = root 5.
Now,
LHS is a rational but RHS is an irrational.
So, our assumption was wrong; 7-root5 is not a rational no.
Therefore, 7-root5 is a irrational no.
Hence, proved.


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☞ ⛧⛧ Mr. Thakur ⛧⛧

Answer 2

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