show that 7-√5 is irrational,given that √5 is irrational
Answers
Answered by
1
Answer:
Step-by-step explanation:
taking 7-sqrt5 in form of a/b where b is not equal to 0
7-root5 = a/b
-Root5 = a/b-7
Taking LCM
-root5 = a-7b/7
a-7b/7 is rational
But given is that root5 is rational
Hence contradiction of our assumption is wrong
7-root5 is irrational
Answered by
0
Answer
Hope it helps
Plz mark it as brainliest if it helped you
Step-by-step explanation:
Attachments:
Similar questions