Question

show that √7 can be expressed on the number line​

Answer 1

Let O be the origin on the line l. 

Let O be the origin on the line l. Let A be on the line such that OA=1. 

Let O be the origin on the line l. Let A be on the line such that OA=1. Draw AB perpendicular to OA at A such that AB=1. Then 

Let O be the origin on the line l. Let A be on the line such that OA=1. Draw AB perpendicular to OA at A such that AB=1. Then OB2=OA2+AB2=12+12=2 Thus OB=2. 

Let O be the origin on the line l. Let A be on the line such that OA=1. Draw AB perpendicular to OA at A such that AB=1. Then OB2=OA2+AB2=12+12=2 Thus OB=2. With O as centre and OB as radius draw an arc cutting the line at C. 

Let O be the origin on the line l. Let A be on the line such that OA=1. Draw AB perpendicular to OA at A such that AB=1. Then OB2=OA2+AB2=12+12=2 Thus OB=2. With O as centre and OB as radius draw an arc cutting the line at C. Then OC=OB=2 

Let O be the origin on the line l. Let A be on the line such that OA=1. Draw AB perpendicular to OA at A such that AB=1. Then OB2=OA2+AB2=12+12=2 Thus OB=2. With O as centre and OB as radius draw an arc cutting the line at C. Then OC=OB=2 Again draw CD prependicular to l such that CD=1. Then 

Let O be the origin on the line l. Let A be on the line such that OA=1. Draw AB perpendicular to OA at A such that AB=1. Then OB2=OA2+AB2=12+12=2 Thus OB=2. With O as centre and OB as radius draw an arc cutting the line at C. Then OC=OB=2 Again draw CD prependicular to l such that CD=1. Then OD2=OC2+CD2=2+1=3. Thus OD=3. 

Let O be the origin on the line l. Let A be on the line such that OA=1. Draw AB perpendicular to OA at A such that AB=1. Then OB2=OA2+AB2=12+12=2 Thus OB=2. With O as centre and OB as radius draw an arc cutting the line at C. Then OC=OB=2 Again draw CD prependicular to l such that CD=1. Then OD2=OC2+CD2=2+1=3. Thus OD=3. Draw an arc with O as centre and OD as radius to cut l in E. Then OE=OD=3.

Let O be the origin on the line l. Let A be on the line such that OA=1. Draw AB perpendicular to OA at A such that AB=1. Then OB2=OA2+AB2=12+12=2 Thus OB=2. With O as centre and OB as radius draw an arc cutting the line at C. Then OC=OB=2 Again draw CD prependicular to l such that CD=1. Then OD2=OC2+CD2=2+1=3. Thus OD=3. Draw an arc with O as centre and OD as radius to cut l in E. Then OE=OD=3.Draw EF prependicular to l at E such that EF = 2 and join OF. Now

Let O be the origin on the line l. Let A be on the line such that OA=1. Draw AB perpendicular to OA at A such that AB=1. Then OB2=OA2+AB2=12+12=2 Thus OB=2. With O as centre and OB as radius draw an arc cutting the line at C. Then OC=OB=2 Again draw CD prependicular to l such that CD=1. Then OD2=OC2+CD2=2+1=3. Thus OD=3. Draw an arc with O as centre and OD as radius to cut l in E. Then OE=OD=3.Draw EF prependicular to l at E such that EF = 2 and join OF. NowOF2=OE2+EF2=3+4=7.

Let O be the origin on the line l. Let A be on the line such that OA=1. Draw AB perpendicular to OA at A such that AB=1. Then OB2=OA2+AB2=12+12=2 Thus OB=2. With O as centre and OB as radius draw an arc cutting the line at C. Then OC=OB=2 Again draw CD prependicular to l such that CD=1. Then OD2=OC2+CD2=2+1=3. Thus OD=3. Draw an arc with O as centre and OD as radius to cut l in E. Then OE=OD=3.Draw EF prependicular to l at E such that EF = 2 and join OF. NowOF2=OE2+EF2=3+4=7.Hence OF=7. With O as centre and OF as radius, cut l at G. 

Let O be the origin on the line l. Let A be on the line such that OA=1. Draw AB perpendicular to OA at A such that AB=1. Then OB2=OA2+AB2=12+12=2 Thus OB=2. With O as centre and OB as radius draw an arc cutting the line at C. Then OC=OB=2 Again draw CD prependicular to l such that CD=1. Then OD2=OC2+CD2=2+1=3. Thus OD=3. Draw an arc with O as centre and OD as radius to cut l in E. Then OE=OD=3.Draw EF prependicular to l at E such that EF = 2 and join OF. NowOF2=OE2+EF2=3+4=7.Hence OF=7. With O as centre and OF as radius, cut l at G. Then OG=OF=7.

Let O be the origin on the line l. Let A be on the line such that OA=1. Draw AB perpendicular to OA at A such that AB=1. Then OB2=OA2+AB2=12+12=2 Thus OB=2. With O as centre and OB as radius draw an arc cutting the line at C. Then OC=OB=2 Again draw CD prependicular to l such that CD=1. Then OD2=OC2+CD2=2+1=3. Thus OD=3. Draw an arc with O as centre and OD as radius to cut l in E. Then OE=OD=3.Draw EF prependicular to l at E such that EF = 2 and join OF. NowOF2=OE2+EF2=3+4=7.Hence OF=7. With O as centre and OF as radius, cut l at G. Then OG=OF=7.Thus G represents 7 on the line l.