show that 7 n cannot end with the digit zero , for any natural number n.
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We know 8n = (23)n = 23n
If 8n end with zero then 10 is factor of 8n.
8n = 23n =(5)(2)
5 is factor of 2, which is a contradiction
So, our assumption is wrong. Hence 8n cannot end with zero
If 8n end with zero then 10 is factor of 8n.
8n = 23n =(5)(2)
5 is factor of 2, which is a contradiction
So, our assumption is wrong. Hence 8n cannot end with zero
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