Math, asked by priyakashyap9748, 1 year ago

Show that 7-root 5 is irrational, give that root 5is irrational.

Answers

Answered by Anonymous
31
\mathfrak{Hey\:Dude!}

\mathfrak{Here's\:your\:answer:}

Given that:

 \sqrt{5}
Is an irrational number.

We need to prove that:

7 \sqrt{5}
Is an irrational number.

There's a property that whenever any irrational number is multiplied by any other irrational number, the resultant number is also an irrational number.

Therefore,

7 \sqrt{5}
Is also an irrational number.

\textbf{Hence Proved!!}

rebelrajardx: unable to understand
rebelrajardx: please give with pic
Anonymous: There's nothing to show in pic
Anonymous: There's jus a property for it
shivam556590: 7_root 5
peenanarula: Unable to understand plz give proper answer
Answered by piyushkumar22
4
Let , 7-root5 is a rational no. is equals to r, where r is a rational no.
So,
7-root 5 = r
7-r = root 5.
Now,
LHS is a rational but RHS is an irrational.
So, our assumption was wrong; 7-root5 is not a rational no.
Therefore, 7-root5 is a irrational no.
Hence, proved.


Hope this will help you...☺☺


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