Show that (7a- 5b)^2 + 140 ab = (7a + 5b)^2
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Answer:
Given (7a - 5b) ^ 2 + 140ab = (7a + 5b) ^ 2
To Find : Prove using identities
solution :
(7a - 5b) ^ 2 + 14ab = (7a + 5b) ^ 2 Using identity (a - b) ^ 2 = a ^ 2 + b ^ 2 - 2ab
(7a)^ 2 +6b)^ 2 -2(7a)(5b)+140 ab=(7a+5b)^ 2
49a² + 25b² Foab +140 ab (7a+56)² 49a ^ 2 + 25b ^ 2 + 70ab = (7a + 5b) ^ 2
こ
(7a) ^ 2 + (5b) ^ 2 + 2(7a) * (5b) = (7a + 5b) ^ 2 (7a + 5b) ^ 2 = (7a + 5b) ^ 2
Hence, the answer is wrified.
Step-by-step explanation:
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