Question

show that 7n cannot end with the digit zero for any natural number n​

Answer 1

Answer:

Step-by-step explanation:

If 7ⁿ ends with a 0 it must be divisible by 10 i.e., its prime factors should have the factors of both 2 and 5 since 2×5=10.

But, 7ⁿ=(7×1)ⁿ

Therefore by the fundamental theorem of arithmetic (there is no prime factors of 7 other than 7 and 1), we can conclude that 7ⁿ can not end with 0.  

hope it helped plz mark me brainliest