show that 7n cannot end with the digit zero for any natural number n
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for the natural number n to end with 0 it would be divisible by 5 or 2
therefore it cannot end with n
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7n = (7 )^1 ✖ n.
The primefactorization of 7n don't consists prime. so, it will not end with zero.
The primefactorization of 7n don't consists prime. so, it will not end with zero.
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