Show that 7root5 is irrational 5 marks
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hey dear here is your answer
let 7√5 be a rational number
then, 7√5 are in the form a/b and a and b are integers and b is not equal to zero
7√5=a/b = √5= a/7b
√5= a/7b
a/7b is a rational number
but √5 is a irrational number
hence , the contradiction we suppose that the 7√5 is rational number is wrong
hence, 7√5 is irrational number..
hope it will help you
thanxx
let 7√5 be a rational number
then, 7√5 are in the form a/b and a and b are integers and b is not equal to zero
7√5=a/b = √5= a/7b
√5= a/7b
a/7b is a rational number
but √5 is a irrational number
hence , the contradiction we suppose that the 7√5 is rational number is wrong
hence, 7√5 is irrational number..
hope it will help you
thanxx
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