Question

Show that 8^n can not end with digit 5.​

Answer 1

Answer:

We know that any number is multiplied by 5 or 10 or by the multiples of 10 ends with zero.

So here the number 8 has factors 1,2,4 and 8.

It does not contain 5 and 10 as prime factors

8n = (2 X 4)n doesn’t have 5 in its prime factorization

Hence, 8n cannot end with the digit 0

hope it helps

pls mark as brainliest

good luck

Answer 2

Explanation:

let the n be 1,2,3,4..

8^1= 8,

8^2= 64,

8^3= 512,

8^4= 4096

...

Therefore we conclude that, in the above process, the number ends only with even number

and 5 is an odd number.