show that 8n can never end with digit 0 for any natural number n
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YOUR SOLUTION IS IN THE ATTACHMENT.
#KEVIN
HOPE IT HELPS YOU ☺
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We know that any positive integer ending with the Zero is divisible by 5 and so it's prime factorisation must contain the prime 5
8ⁿ = ( 2 )³ⁿ
=> The only prime in the factorisation of 8ⁿ is 2
=> 5 doesn't occur in the prime factorisation of 8ⁿ
=> 8ⁿ doesn't end with the digit Zero for any natural number n.
8ⁿ = ( 2 )³ⁿ
=> The only prime in the factorisation of 8ⁿ is 2
=> 5 doesn't occur in the prime factorisation of 8ⁿ
=> 8ⁿ doesn't end with the digit Zero for any natural number n.
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