Question

show that 8n cannot be end the digit 5 for any natural number n​

Answer 1

Step-by-step explanation:

For a number to end with the digit 0 it's prime factorization should have 2 and 5 as a common factor. here 8^n = (2*4)^n doesn't have 5 in its prime factorization. Therefore 8^n cannot end with the digit 0.