Show that 8n cannot end with the digit zero for any natural number n
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Answered by
2
Answer:
If it is 8n then it can end with 0 but if it is 8ⁿ then it can't end with 0.
For a number to end with the digit 0 it's prime factorisation should have 2 and 5 as a common factor.
here 8ⁿ = (2*4)ⁿ doesn't have 5 in its prime factorisation.
Therefore 8ⁿ cannot end with the digit 0.
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Answered by
0
Answer:
your answer is here
Step-by-step explanation:
We know 8n = (2 to the power 3)n = 2 to the power 3 n
If 8n end with zero then 10 is factor of 8n.
8n = 2 to the power 3n = (5)(2)
5 is factor of 2, which is a contradiction
So, our assumption is wrong. Hence 8n cannot end with zero
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