show that 9 n can't end with 2 for any integer n
Answers
Answered by
5
there's a example to understand easily
Q How do you show that 12 to the power of n cannot end with the digit 0 or 5 for any natural number n?
ans . All numbers ending with a '5' are multiples of 5, which is to say that they have 5 as a factor. (Numbers ending with '0' are even multiples of 5, and numbers ending with '5' are odd multiples.)
12 = 2 × 2 × 3, which doesn't have any factors of 5. Since taking the nth power of a number just multiplies a number by itself n times, no factor of 5 can be introduced by doing this, so no power of 12 can end with a '0' or '5'.
Q How do you show that 12 to the power of n cannot end with the digit 0 or 5 for any natural number n?
ans . All numbers ending with a '5' are multiples of 5, which is to say that they have 5 as a factor. (Numbers ending with '0' are even multiples of 5, and numbers ending with '5' are odd multiples.)
12 = 2 × 2 × 3, which doesn't have any factors of 5. Since taking the nth power of a number just multiplies a number by itself n times, no factor of 5 can be introduced by doing this, so no power of 12 can end with a '0' or '5'.
Similar questions