show that 9 n cannot end with digit 0 for any natural number
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hey mate !!!
For any integer to end with zero, their prime factorization must contain 2 and 5.
prime factorization of 9 n
= (3×3)n
it is clear from the above prime factorization that 9 neither has 2 nor 5 in its prime factorization hence 9n cannot end with digit 0 for any natural number.
hope you've found it informative!!
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